CS501 Advance Computer Architecture ASSIGNMENT 5 SOLUTION

	Assignment No. 05 SOLUTION Semester Spring 2011 Advance Computer Architecture - CS501				Total Marks: 20 Due Date: 01/07/2011
Objective: To learn and understand basic concepts of disk drives, and error control Instructions: Please read the following instructions carefully before solving & submitting assignment: Assignment should be in your own wordings not copied from net, handouts or books. It should be clear that your assignment will not get any credit (zero marks) if: The assignment is submitted after due date. The submitted assignment does not open or file corrupt. The assignment is copied (from other student or copy from handouts or internet). Student ID is not mentioned in the assignment File or name of file is other than student ID. Note: You have to provide solution with all the calculations and formulations involved, else no marks will be awarded. For any query about the assignment, contact at cs501@vu.edu.pk GOOD LUCK
Question No 1			10 Marks
A hard drive has 4 surfaces, with 512 tracks per surface and constant 64 sectors per track. Sector size is 2K byte. The average seek time is 3 ms, the drive runs at 3,600 rpm. What is the drive capacity? (5) What is average access time for the drive? (5) Solution: Capacity = 4 x 512 x 64 x 2K= 262144 KB Rotational latency = Rotation time/ 2 = 60/ 3600x2 = 8.3 ms Average access time= Seek time + Rotational latency = 3 + 8.3 = 11.3 ms
Question No 2				10 Marks
Use the hamming code to encode the following 4-bit values (8 marks) Also write down the encoding scheme (2 mark)  Total (8+2 = 10 marks) A.                0110 B.                 1001 C.                0000 D.                1111 Note : Use odd bit parity to encode above values Solution: The encoding scheme is P1P2D3P4D5D6D7 , using odd parity 0110 → 0001110 1001 → 1110001 0000 → 1101000 1111 → 0010111

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By: Digital Communication

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